Schlagwort-Archive: art

Film “Abs.: KHS” in den Kunstsammlungen Chemnitz

Kunstsammlungen Chemnitz

In der Ausstellung “Hommage an Klaus Hähner-Springmühl” in den Kunstsammlungen Chemnitz (11. Mai 2014 bis zum 29. Juni 2014) gibt es noch einmal die Gelegenheit den Film “Abs.: Klaus Hähner-Springmühl – Richterstraße 9″ auf großer Leinwand zu sehen…

Hier der Link zur Ausstellung: Hommage an Klaus Hähner-Springmühl

Wir freuen uns auf Ihren Besuch.

Kunstsammlungen Chemnitz
Theaterplatz 1
09111 Chemnitz


Emerson Gallery Berlin presents: HEADS WILL ROLL

An evening with selected short films by Richard Sylvarnes.


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With live music accompagnement by
Klaus Killisch (
Enkidu Rankx (
Richard Sylvarnes (

(c) Sulamith Sallmann

(c) Sulamith Sallmann

Emerson Gallery Berlin
27.09.2013 – 19h00
Schiffbauerdamm 19
10117 Berlin


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I am quiet busy with my project / exhibition. Now is the time to swing the public relational hammer indeed! So be prepared to be massively advertised and properly informed about Da Product.


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Verlauf / rain in motion (RiDream)


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“Verlauf / rain in motion (RiDream)”, HD-Video, 4:02 min, 2013
music by MK_ultra: “RiDream” from the album “Mind the Gap”
filmend on the way from Leipzig to Berlin

the code is cold | trailer #2


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5 Degrees Of Separation – Premiere @ Pottporus Festival

5 Degrees Of Separation by KooneCompany

Weitere Bilder und Infos zur Premiere hier >>

“As KooneCompany was chosen by the Goethe Institut Montreal for their Dance Residency Programm in summer 2011, we created the 1 hour length piece: “5 Degrees Of Separation” .
After the good work in Montreal we take the next step and show the premiere of the piece on the 3rd of november in Herne at the Kulturzentrum Herne… The premiere will be part of the well known “Pottporus Festival” initiated by Pottporus e.V. / Renegade Theatre .”


Und hier das ursprüngliche Konzept von uns >>

code poetry


RANKX-Funktion (DAX): RANKX(<table>, <expression>[, <value>[, <order>[, <ties>]]])
Proving rank(℘(x))=rank(x)+
Enderton defines the rank of a set A to be the least ordinal α such that A⊆Vα (equivalently, A∈Vα+). He the derives the following identity: rank(A)=⋃{(rank(x))+:x∈A} for all sets A.
In Exercise 30 of Chapter 7, the reader is asked to prove several identities involving rank. For instance, that rank{a,b}=max(rank(a),rank(b))+. I am having trouble proving the second identity, that rank(℘(x))=rank(x)+ for all sets x. I am not sure whether I am missing some elementary identity that would let me prove the identity, or whether I am misunderstanding the definition of rank.
Clearly, z∈rank(℘(x))⇔(∃y)(y⊆x∧(z∈rank(y)∨z=rank(y)). On the other hand z∈(rank(x))+⇔(∃y)(y∈x∧z∈(rank(y))+)∨z=rank(x). I'm not sure why the first statement should imply the second, and conversely, however.
>> elementary-set-theory

Now isn’t that poetic…